xxxxxxxxxx
mylist = ["a", "b", "a", "c", "c"]
mylist = list(dict.fromkeys(mylist))
xxxxxxxxxx
mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)
xxxxxxxxxx
# remove duplicate from given_list using list comprehension
res = []
[res.append(x) for x in given_list if x not in res]
xxxxxxxxxx
# HOW TO REMOVE DUPLICATES FROM A LIST:
# 1) CREATE A LIST
my_list = [1, 2, 3, 4, 5, 5, 5, 1]
# 2) CONVERT IT TO A SET AND THEN BACK INTO A LIST
my_list = list(set(my_list))
# 3) DONE!
print(my_list) #WILL PRINT: [1, 2, 3, 4, 5]
xxxxxxxxxx
mylist = ["a", "b", "a", "c", "c"]
mylist = list(dict.fromkeys(mylist))
print(mylist)
xxxxxxxxxx
def remove_dupiclates(list_):
new_list = []
for a in list_:
if a not in new_list:
new_list.append(a)
return new_list
xxxxxxxxxx
bad_list = ["hi", 1, 2, 2, 3, 5, "hi", "hi"]
good_list = list(set(bad_list))
xxxxxxxxxx
word = input().split()
for i in word:
if word.count(i) > 1:
word.remove(i)
xxxxxxxxxx
# Python 3 code to demonstrate
# removing duplicated from list
# using naive methods
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using naive method
# to remove duplicated
# from list
res = []
for i in test_list:
if i not in res:
res.append(i)
# printing list after removal
print ("The list after removing duplicates : " + str(res))