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def dedupe(items):
seen = set()
for item in items:
if item not in seen:
yield item
seen.add(item)
a = [1, 5, 2, 1, 9, 1, 5, 10]
list(dedupe(a))# [1, 5, 2, 9, 10]
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mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)
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# remove duplicate from given_list using list comprehension
res = []
[res.append(x) for x in given_list if x not in res]
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# HOW TO REMOVE DUPLICATES FROM A LIST:
# 1) CREATE A LIST
my_list = [1, 2, 3, 4, 5, 5, 5, 1]
# 2) CONVERT IT TO A SET AND THEN BACK INTO A LIST
my_list = list(set(my_list))
# 3) DONE!
print(my_list) #WILL PRINT: [1, 2, 3, 4, 5]
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mylist = ["a", "b", "a", "c", "c"]
mylist = list(dict.fromkeys(mylist))
print(mylist)
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my_list = [1,2,2,3,1,4,5,1,2,6]
myFinallist = []
for i in my_list:
if i not in myFinallist:
myFinallist.append(i)
print(list(myFinallist))
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bad_list = ["hi", 1, 2, 2, 3, 5, "hi", "hi"]
good_list = list(set(bad_list))
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# ----- Create a list with no repeating elements ------ #
mylist = [67, 7, 89, 7, 2, 7]
newlist = []
for i in mylist:
if i not in newlist:
newlist.append(i)
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# Python 3 code to demonstrate
# removing duplicated from list
# using naive methods
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using naive method
# to remove duplicated
# from list
res = []
for i in test_list:
if i not in res:
res.append(i)
# printing list after removal
print ("The list after removing duplicates : " + str(res))
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olist= ["a", "a", "b", "c", "d", "e", "f"]
tlist = []
for x in range(0, len(olist)):
intlist = False
for y in range(0, len(tlist)):
if(olist[x] == tlist[y]):
intlist = True
if(intlist == False):
tlist.append(olist[x])
print(tlist)
#['a', 'b', 'c', 'd', 'e', 'f', 1, 2]