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duplicate = [2, 4, 10, 20, 5, 2, 20, 4]
print(list(set(duplicate))
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mylist = ["a", "b", "b", "c", "a"]
mylist = sorted(set(mylist))
print(mylist)
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# remove duplicate from given_list using list comprehension
res = []
[res.append(x) for x in given_list if x not in res]
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def remove_dupiclates(list_):
new_list = []
for a in list_:
if a not in new_list:
new_list.append(a)
return new_list
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my_list = [1,2,2,3,1,4,5,1,2,6]
myFinallist = []
for i in my_list:
if i not in myFinallist:
myFinallist.append(i)
print(list(myFinallist))
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bad_list = ["hi", 1, 2, 2, 3, 5, "hi", "hi"]
good_list = list(set(bad_list))
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word = input().split()
for i in word:
if word.count(i) > 1:
word.remove(i)
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# Python 3 code to demonstrate
# removing duplicated from list
# using naive methods
# initializing list
test_list = [1, 3, 5, 6, 3, 5, 6, 1]
print ("The original list is : " + str(test_list))
# using naive method
# to remove duplicated
# from list
res = []
for i in test_list:
if i not in res:
res.append(i)
# printing list after removal
print ("The list after removing duplicates : " + str(res))